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Question: 10 gm of NaOH is present in 90 gm of water. Find out mole fraction of NaOH....

10 gm of NaOH is present in 90 gm of water. Find out mole fraction of NaOH.

Answer

0.0476

Explanation

Solution

  1. Calculate moles of NaOH:

Moles of NaOH = mass/molar mass = 10 g / 40 g/mol = 0.25 mol

  1. Calculate moles of H₂O:

Moles of H₂O = 90 g / 18 g/mol = 5 mol

  1. Determine mole fraction of NaOH:

Mole fraction = moles of NaOH / (moles of NaOH + moles of H₂O)
= 0.25 / (0.25 + 5) = 0.25 / 5.25 ≈ 0.0476