Question

An isosceles triangular current carrying loop $PQR$ is kept perpendicularly in a uniform magnetic field $B_0$ as shown in figure. The force on the loop due to magnetic field is

Answer 1

0

Answer 2

The force on a closed current loop in a uniform magnetic field is given by $\vec{F} = I (\oint d\vec{l}) \times \vec{B}$. For any closed loop, the vector sum of infinitesimal displacement vectors $\oint d\vec{l}$ is zero. Therefore, the total force on the loop is zero.