Question

$18.4$ g of is taken in a 1 L closed vessel and heated till the equilibrium is reached.

$\mathrm { N } _ { 2 } \mathrm { O } _ { 4 ( \mathrm {~g} ) }$

At equilibrium it is found that 50% of is dissociated. What will be the value of equilibrium constant?

• A. $0.2$
• B. 2
• C. $0.4$
• D. $0.8$

Answer 1

Answer: (C)

$0.4$

Answer 2

: $\mathrm { N } _ { 2 } \mathrm { O } _ { 4 ( \mathrm {~g} ) }$

Initial conc. $18.4$ 0

No. of moles $\frac { 18.4 } { 92 } = 0.2$

At equilibrium $0.2 - 0.1$

$= 0.1$ $= 0.2$

$\mathrm { K } _ { \mathrm { c } } = \frac { 0.2 \times 0.2 } { 0.1 } = 0.4$