Question

18.0 sec are required for the diffusion of x mol of O₂ through some porous partition. Another gas G requires 45.0 sec for the diffusion of x mol through the same partition under similar conditions, the molar mass of G is –

• A. $\left( \frac { 45 } { 18 } \right) ^ { 2 } \times ( 32 )$
• B. $\left( \frac { 45 \times ( 32 ) } { 18 } \right) ^ { 2 }$
• C. $\left( \frac { 18 } { 45 } \right) ^ { 2 } \times 32$
• D. $\left( \frac { 18 } { 45 } \right) ^ { 2 } \times \frac { 1 } { 32 }$

Answer 1

Answer: (A)

$\left( \frac { 45 } { 18 } \right) ^ { 2 } \times ( 32 )$

Answer 2

=