Question

The energy required to move $\Delta V.q$ The potential difference between

• A. 100 V
• B. 256 V
• C. 200 V
• D. 128 $\stackrel{\circ}{V}=6.4\times10^{10}$ $=64J$

Answer 1

Answer: (C)

200 V

Answer 2

The potential difference $V$ is calculated using the formula:

$$V = \frac{W}{q}$$

Where:

• $W$ is the work done (energy required) to move the charge.
• $q$ is the magnitude of the charge.

Given $W = 50 \, \text{J}$ and $q = 0.25 \, \text{C}$:

$$V = \frac{50 \, \text{J}}{0.25 \, \text{C}} = 200 \, \text{V}$$

Therefore, the potential difference between the two points is 200 V.