(18.72, g) of a substance ('X') occupies (1.81 ,cm^3). What... | Chemistry | SolveeIt

Question

$18.72\, g$ of a substance $'X'$ occupies $1.81 \,cm^3$ . What will be its density measured in correct significant figures?

$10.3 \,g \,cm^{3}$

$10.34 \,g \,cm^{3}$

$10.4 \,g \,cm^{3}$

$10.3425 \,g \,cm^{3}$

Answer

$10.3 \,g \,cm^{3}$

Explanation

Solution

Density $= \frac{\text{Mass}}{\text{Volume}}$ $= \frac{18.72}{1.81}$ $= 1.34 \,g\, cm^{-3}$ Since volume contains $3$ significant figures hence answer will be $10.3 \,g\, cm^{-3}$

Chemistry Question on Some basic concepts of chemistry

Solution