Question

17 mg of a hydrocarbon (M.F. C10H16) takes up 8.40 mL of the H2 gas measured at $0\degree C$ and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is_______.

Answer 1

The correct answer is 3
C10 H16 + H 2 🡢
17x10-3/136 1x8.4x10-3/0.082x273
0.125 milli moles 0.375 milli moles
0.125 milli moles of C10H16 required 0.375 milli moles of H2 therefore there are total 3 $\pi$-bonds.
therefore DOU will also be equal to 3