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Question: 1.5 mW of 400 nm light is directed at a photo electric cell. If 0.1% of the incident photons produce...

1.5 mW of 400 nm light is directed at a photo electric cell. If 0.1% of the incident photons produce photo electrons, the current in the cell is-

A

0.48µA

B

0.42mA

C

0.48 mA

D

0.42µA

Answer

0.48µA

Explanation

Solution

n =

ne = n × β % = × β100\frac { \beta } { 100 }

ne = 1.5×10−3×400×10−96.6×10−34×3×108\frac { 1.5 \times 10 ^ { - 3 } \times 400 \times 10 ^ { - 9 } } { 6.6 \times 10 ^ { - 34 } \times 3 \times 10 ^ { 8 } } × 0.1100\frac { 0.1 } { 100 }

I = ne e

= 0.48 µA