Question

15 joule of work has to be done against an existing electric field to take a charge of 0.01 C from A to B. Then the potential difference (V_B – V_A) is –

• A. 1500 volt
• B. –1500 volt
• C. 0.15 volt
• D. None of these

Answer 1

Answer: (A)

1500 volt

Answer 2

W_ext = q(V_B – V_A); V_B – V_A = $\frac { 15 } { .01 }$=1500 volt