Question
Question: Find the temperature distribution in the space between two coaxial cylinders of radii $R_1$ and $R_2...
Find the temperature distribution in the space between two coaxial cylinders of radii R1 and R2 filled with a uniform heat conducting substance if the temperatures of the cylinders are constant and are equal to T1 and T2 respectively.

T(r)=ln(R2/R1)T1ln(R2/r)+T2ln(r/R1)
T(r)=T1+ln(R2/R1)T2−T1ln(R1r)
T(r)=ln(R2/R1)T1ln(r/R1)+T2ln(R2/r)
T(r)=T2+ln(R1/R2)T1−T2ln(R2r)
T(r)=ln(R2/R1)T1ln(R2/r)+T2ln(r/R1)
Solution
The problem involves steady-state heat conduction in a medium with radial symmetry. The governing differential equation in cylindrical coordinates for constant thermal conductivity is: r1drd(rdrdT)=0 Integrating this equation twice with respect to r yields the general solution for the temperature distribution: T(r)=C1ln(r)+C2 The constants C1 and C2 are determined using the boundary conditions: T(R1)=T1 and T(R2)=T2. Applying the boundary conditions:
- T1=C1ln(R1)+C2
- T2=C1ln(R2)+C2
Subtracting equation (1) from equation (2): T2−T1=C1(ln(R2)−ln(R1))=C1ln(R2/R1) So, C1=ln(R2/R1)T2−T1.
Substitute C1 back into equation (1) to find C2: C2=T1−C1ln(R1)=T1−ln(R2/R1)T2−T1ln(R1).
Substituting C1 and C2 into the general solution: T(r)=ln(R2/R1)T2−T1ln(r)+T1−ln(R2/R1)T2−T1ln(R1) T(r)=T1+ln(R2/R1)T2−T1(ln(r)−ln(R1)) T(r)=T1+ln(R2/R1)T2−T1ln(R1r) This can be rearranged into a more symmetric form: T(r)=ln(R2/R1)T1ln(R2/R1)+(T2−T1)ln(r/R1) T(r)=ln(R2/R1)T1(ln(R2)−ln(R1))+T2ln(r/R1)−T1ln(r/R1) T(r)=ln(R2/R1)T1ln(R2)−T1ln(R1)+T2(ln(r)−ln(R1))−T1(ln(r)−ln(R1)) T(r)=ln(R2/R1)T1ln(R2)−T1ln(R1)+T2ln(r)−T2ln(R1)−T1ln(r)+T1ln(R1) T(r)=ln(R2/R1)T1ln(R2)+T2ln(r)−T2ln(R1)−T1ln(r) T(r)=ln(R2/R1)T1(ln(R2)−ln(r))+T2(ln(r)−ln(R1)) T(r)=ln(R2/R1)T1ln(R2/r)+T2ln(r/R1)