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Question

Question: A point moves in the xy plane according to the equations $x = a \sin \omega t$ and $y = a \cos \omeg...

A point moves in the xy plane according to the equations x=asinωtx = a \sin \omega t and y=acosωty = a \cos \omega t. The particle has a trajectory

A

an elliptical path

B

a circular path

C

a parabolic path

D

a straight line path inclined equally to x and y-axes

Answer

a circular path

Explanation

Solution

Given:

x=asinωt,y=acosωtx = a\sin\omega t, \quad y = a\cos\omega t

Divide both equations by aa:

xa=sinωt,ya=cosωt\frac{x}{a} = \sin\omega t, \quad \frac{y}{a} = \cos\omega t

Squaring and adding:

(xa)2+(ya)2=sin2ωt+cos2ωt=1\left(\frac{x}{a}\right)^2 + \left(\frac{y}{a}\right)^2 = \sin^2\omega t + \cos^2\omega t = 1

Thus,

x2+y2=a2x^2 + y^2 = a^2

This is the equation of a circle of radius aa.