Solveeit Logo

Question

Question: Consider two set up shown in diagram, liquid is ideal (surface tension and viscosity can be neglecte...

Consider two set up shown in diagram, liquid is ideal (surface tension and viscosity can be neglected). Choose correct option(s).

A

PBPA=PDPCP_B-P_A = P_D-P_C i.e. pressure difference between corresponding points in two cases is same

B

PBPA<PDPCP_B-P_A < P_D-P_C

C

PBPA>PDPCP_B-P_A > P_D-P_C

Answer

PBPA=PDPCP_B-P_A = P_D-P_C i.e. pressure difference between corresponding points in two cases is same

Explanation

Solution

The pressure difference between two points in a fluid at rest is given by ΔP=ρgΔh\Delta P = \rho g \Delta h, where ρ\rho is the density of the fluid, gg is the acceleration due to gravity, and Δh\Delta h is the vertical distance between the two points. Since the vertical distances between A and B, and between C and D are the same, and the liquid is the same, the pressure difference PBPAP_B - P_A is equal to PDPCP_D - P_C. The shape of the container does not affect hydrostatic pressure difference.