Question
Question: Consider the circles $C_1: x^2 + y^2 = 16$ and $C_2: x^2 + y^2 - 12x + 32 = 0$. Which of the followi...
Consider the circles C1:x2+y2=16 and C2:x2+y2−12x+32=0. Which of the following statement is/are correct?

Number of common tangent to these circles is 3.
The point P with coordinates (4,1) lies outside the circle C1 and inside the circle C2.
Their direct common tangent intersect at (12,0).
Slope of their radical axis is not defined.
(A), (C), and (D)
Solution
Circle C1: x2+y2=16 has center O1=(0,0) and radius r1=4.
Circle C2: x2+y2−12x+32=0. Completing the square: (x−6)2+y2=4. This circle has center O2=(6,0) and radius r2=2.
The distance between the centers O1 and O2 is d=(6−0)2+(0−0)2=6.
The sum of the radii is r1+r2=4+2=6. Since d=r1+r2, the circles touch externally.
Let's analyze each statement:
(A) Number of common tangents: When two circles touch externally, they have exactly 3 common tangents (2 direct and 1 transverse). So, statement (A) is correct.
(B) Position of point P(4,1): For C1: 42+12−16=16+1−16=1. Since 1>0, P is outside C1. For C2: (4−6)2+12−4=(−2)2+1−4=4+1−4=1. Since 1>0, P is outside C2. The statement claims P is outside C1 (true) and inside C2 (false). So, statement (B) is incorrect.
(C) Intersection of direct common tangents: The direct common tangents intersect at the exsimilicenter, which divides the line segment joining the centers externally in the ratio of their radii (r1:r2=4:2=2:1). Using the external division formula for O1(0,0) and O2(6,0): T=(2−12×6−1×0,2−12×0−1×0)=(112,10)=(12,0). So, statement (C) is correct.
(D) Slope of the radical axis: The radical axis is found by C1−C2=0. (x2+y2−16)−(x2+y2−12x+32)=0 12x−48=0 x=4. This is a vertical line, whose slope is undefined. So, statement (D) is correct.
The correct statements are (A), (C), and (D).