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Question: A quantity of 22 g dry ice is taken in an open bottle of one litre capacity and the bottle is then c...

A quantity of 22 g dry ice is taken in an open bottle of one litre capacity and the bottle is then closed properly. If the temperature of bottle is maintained at 27°C for long time, in which all the CO₂ is sublimed, then the pressure in bottle is (Ambient condition is 1 atm and 27°C)

A

13.315 atm

B

12.315 atm

C

11.315 atm

D

1.0 atm

Answer

13.315 atm

Explanation

Solution

The total pressure is the sum of the partial pressure of the trapped air and the partial pressure of the CO₂ gas.

  1. Moles of CO₂: nCO2=22 g44 g/mol=0.5 moln_{CO_2} = \frac{22 \text{ g}}{44 \text{ g/mol}} = 0.5 \text{ mol}.
  2. Partial Pressure of CO₂ (PCO2P_{CO_2}): Using the Ideal Gas Law, PCO2=nCO2RTV=0.5 mol×0.0821 L\cdotpatm/(mol\cdotpK)×300 K1 L=12.315 atmP_{CO_2} = \frac{n_{CO_2}RT}{V} = \frac{0.5 \text{ mol} \times 0.0821 \text{ L·atm/(mol·K)} \times 300 \text{ K}}{1 \text{ L}} = 12.315 \text{ atm}.
  3. Partial Pressure of Trapped Air (PairP_{air}): Since the bottle was open to the atmosphere at 1 atm, Pair=1 atmP_{air} = 1 \text{ atm}.
  4. Total Pressure (PtotalP_{total}): Ptotal=Pair+PCO2=1 atm+12.315 atm=13.315 atmP_{total} = P_{air} + P_{CO_2} = 1 \text{ atm} + 12.315 \text{ atm} = 13.315 \text{ atm}.