Question

125 identical drops each charged to the same potential of $50\mspace{6mu} volts$are combined to form a single drop. The potential of the new drop will be

• A. $50V$
• B. $250\mspace{6mu} V$
• C. $500\mspace{6mu} V$
• D. $1250\mspace{6mu} V$

Answer 1

Answer: (D)

$1250\mspace{6mu} V$

Answer 2

V = n^2/3 v ⇒ V = (125)^2/3 × 50 = 1250 V