Question

In which of the following oxides, nitrogen exhibit +4 oxidation state?

• A. N₂O₅
• B. N₂O₄
• C. N₂O
• D. N₂O₅

Answer 1

Answer: (B)

N₂O₄

Answer 2

For $\ce{N2O4}$:

$$2x + 4(-2) = 0 \quad \Rightarrow \quad 2x - 8 = 0 \quad \Rightarrow \quad 2x = 8 \quad \Rightarrow \quad x = +4.$$

Thus, nitrogen exhibits a +4 oxidation state in $\ce{N2O4}$.

Core Explanation:
Assign oxidation state $x$ to nitrogen and set up the equation $2x + 4(-2)=0$. Solve to get $x=+4$.