Question

In which of the following oxides, nitrogen exhibit +4 oxidation state?

• A. N₂O₅
• B. N₂O₄
• C. N₂O
• D. N₂O₅

Answer 1

Answer: (B)

N₂O₄

Answer 2

For N₂O₄, let the oxidation state of N = x.

$$2x + 4(-2) = 0 \quad \Rightarrow \quad 2x - 8 = 0 \quad \Rightarrow \quad x = +4$$

Thus, nitrogen exhibits a +4 oxidation state in N₂O₄.

Using the oxidation state sum for N₂O₄: $2x + 4(-2) = 0$ Solving gives $x = +4$.