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Question: During an adiabatic process the cube of the pressure of a gas is proportional to the fifth power of ...

During an adiabatic process the cube of the pressure of a gas is proportional to the fifth power of its volume. The ratio of specific heat Cp/CvC_p/C_v for that gas is

A

3/5

B

4/3

C

3/2

D

5/3

Answer

5/3

Explanation

Solution

The problem states that during an adiabatic process, the cube of the pressure of a gas is proportional to the fifth power of its volume. We need to find the ratio of specific heats Cp/CvC_p/C_v for this gas.

Let P be the pressure and V be the volume of the gas.
According to the problem statement, P3V5P^3 \propto V^5.
This can be written as P3=kV5P^3 = k V^5, where k is a constant.
Rearranging this, we get P3V5=kP^3 V^{-5} = k.

The general equation for an adiabatic process is PVγ=constantPV^\gamma = \text{constant}, where γ=Cp/Cv\gamma = C_p/C_v.

If we compare P3V5=kP^3 V^{-5} = k with the standard adiabatic equation, we first need to make the pressure term match. Let's raise the standard adiabatic equation to the power of 3:
(PVγ)3=(constant)3(PV^\gamma)^3 = (\text{constant})^3
P3V3γ=constantP^3 V^{3\gamma} = \text{constant}'

Now, comparing P3V5=kP^3 V^{-5} = k with P3V3γ=constantP^3 V^{3\gamma} = \text{constant}', we would get 3γ=53\gamma = -5, which implies γ=5/3\gamma = -5/3. This value of γ\gamma is not physically possible for a gas, as γ\gamma must be positive and greater than 1 (since Cp>CvC_p > C_v).

In such physics problems, when "proportional to" is used, and it leads to a non-physical result, it often implies an inverse proportionality. Given the options, it is highly probable that the intended meaning is that the cube of the pressure is proportional to the inverse fifth power of its volume, or more simply, the product of the cube of the pressure and the fifth power of the volume is constant.
So, we assume the relationship is P3V5=constantP^3 V^5 = \text{constant}.

Now, let's convert this assumed relation to the standard adiabatic form PVγ=constantPV^\gamma = \text{constant}.
We have P3V5=constantP^3 V^5 = \text{constant}.
To get P to the power of 1, we take the cube root of both sides:
(P3V5)1/3=(constant)1/3(P^3 V^5)^{1/3} = (\text{constant})^{1/3}
P(3×1/3)V(5×1/3)=new constantP^{(3 \times 1/3)} V^{(5 \times 1/3)} = \text{new constant}
P1V5/3=new constantP^1 V^{5/3} = \text{new constant}

Comparing this equation, PV5/3=new constantP V^{5/3} = \text{new constant}, with the standard adiabatic equation PVγ=constantPV^\gamma = \text{constant}, we can directly identify the value of γ\gamma:
γ=5/3\gamma = 5/3

This value is physically plausible, as γ=5/3\gamma = 5/3 corresponds to a monatomic gas.