( \_{11}N{{a}^{23}} ) is formed from ( \_{11}N{{a}^{24}} ) b... | Chemistry | SolveeIt

$_{11}N{{a}^{23}}$ is formed from $_{11}N{{a}^{24}}$ by the

$_{0}{{n}^{1}}$ emission

$\beta -$ emission

$K-$ electron capture

$\alpha -$ emission

Answer

$_{0}{{n}^{1}}$ emission

Explanation

$_{11}N^{24} \to \,_{11}N^{23} + \,_{0}n^{1}$ Because of emission of neutron, $_{11}Na^{23}$ is formed.

Chemistry Question on Nuclear physics