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Question: \(100c{m^3}\) of a given sample of \({H_2}{O_2}\) gives \(1000 \;c{m^3}\) of \({O_2}\) at S.T.P. the...

100cm3100c{m^3} of a given sample of H2O2{H_2}{O_2} gives 1000  cm31000 \;c{m^3} of O2{O_2} at S.T.P. the given sample is:
A) 1010% {H_2}{O_2}
B) 9090% {H_2}{O_2}
C) 1010 volume H2O2{H_2}{O_2}
D) 100100 volume H2O2{H_2}{O_2}

Explanation

Solution

Hydrogen peroxide is a chemical compound with the formula H2O2{H_2}{O_2}. H2O2{H_2}{O_2} on catalytic Decomposition breaks down to give molecules of water and oxygen H2{H_2} and O2{O_2}.

Complete answer:
Decomposition is catalysed by various transition metals and their compounds. It is highly unstable in nature and it is stored with a stabilizer in a weakly acidic solution in a dark colored bottle.
he decomposition reaction of H2O2{H_2}{O_2} is:
H2O2H2O+12O2{H_2}{O_2} \to {H_2}O + \dfrac{1}{2}{O_2}
12\dfrac{1}{2} mole of O2{O_2} is obtained from 34  g  H2O234\;g\;{H_2}{O_2} .
11 ml of H2O2{H_2}{O_2} will give 1010ml from O2{O_2} at STP
10 volume’ means that 10 cm3cm^3 of oxygen gas is produced by every 1 cm3cm^3 of hydrogen peroxide. Thus for every 100cm3100c{m^3} the oxygen liberated is 1000cm31000c{m^3}. The sample of H2O2{H_2}{O_2} which will be required is
1ooocm3100cm3=10cm3\dfrac{{1oooc{m^3}}}{{100c{m^3}}} = 10c{m^3}
Hence for the 1000cm31000c{m^3} of O2{O_2} 10 times the volume of the sample is required.

Therefore the correct option is option (C) .

Additional Information: Hydrogen peroxide has been used as a propellant in rockets and torpedoes. This is because the decomposition reaction can be speeded up greatly by adding a catalyst. Producing a large volume of gas in a short time and small space creates a lot of energy.

Note: The reaction happens slowly while hydrogen peroxide is stored, because unevenness in the container’s surface can help to split the molecule – one part gets stuck to the surface while the other part pulls away.