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Question: 100 ml of given \(KMn{{O}_{4}}\) titrates 50 ml of 0.1M Oxalic acid. Its normality against alkaline ...

100 ml of given KMnO4KMn{{O}_{4}} titrates 50 ml of 0.1M Oxalic acid. Its normality against alkaline H2O2{{H}_{2}}{{O}_{2}} is:
A. 0.1 N
B. 0.02 N
C. 0.06 N
D. None of the above

Explanation

Solution

Hint: A certain amount of milliequivalents of KMnO4KMn{{O}_{4}} will titrate the same amount of milliequivalents of oxalic acid. Also, remember that the n-factor of KMnO4KMn{{O}_{4}} varies in acidic and basic medium.

Step-by-Step Solution:
Let us first go through the properties of Potassium Permanganate (KMnO4KMn{{O}_{4}}) as a compound.
Potassium permanganate is an inorganic compound with the chemical formula KMnO4KMnO_4 and composed of K+ and MnO4MnO^{4-}. It is a purplish-black crystalline solid that dissolves in water to give intensely pink or purple solutions.
Potassium permanganate is widely used in the chemical industry and laboratories as a strong oxidizing agent, and also as a medication for dermatitis, for cleaning wounds, and general disinfection.
Having established the properties and usage of KMnO4KMn{{O}_{4}}, let us now move on to the particulars of this question.
Now, we know that Oxalic Acid’s chemical formula is COOHCOOHCOOH-COOH and due to its presence in the initial titration, the medium would thus be acidic.
However, the later titration is done against alkaline H2O2{{H}_{2}}{{O}_{2}} where the medium would be alkaline in nature.
With all this information now at our disposal along with the hint, let us now proceed to the step-by-step solution:

& Milliequivalents\text{ }of\text{ }oxalic\text{ }acid~=50\times 0.1\times 2=10 \\\ & \because Initial\text{ }medium\text{ }is\text{ }acidic~(\Rightarrow n=5~for~KMnO4). \\\ & \therefore ~Molarity\text{ }of~KMn{{O}_{4}}=\dfrac{N}{5}=\dfrac{\dfrac{10}{100}}{5}=0.02M \\\ & In\text{ }alkaline\text{ }medium,~\text{ }n=3~for~KMn{{O}_{4}}~ \\\ & Hence,\text{ }normality~=0.02\times 3~=0.06N \\\ \end{aligned}$$ Therefore, by our calculations, we can safely conclude that the required normality of $KMn{{O}_{4}}$ is 0.06N making the answer to this question c) 0.06N. Note: Absolute caution must be taken during the titrations of any acidic or alkaline substance, regardless of its strength, so as to avoid any form of injury or damage. Also make sure that no mistakes are made in the n- factor calculation of Potassium Permanganate w.r.t change in mediums.