Question
Question: 100 ml of given \(KMn{{O}_{4}}\) titrates 50 ml of 0.1M Oxalic acid. Its normality against alkaline ...
100 ml of given KMnO4 titrates 50 ml of 0.1M Oxalic acid. Its normality against alkaline H2O2 is:
A. 0.1 N
B. 0.02 N
C. 0.06 N
D. None of the above
Solution
Hint: A certain amount of milliequivalents of KMnO4 will titrate the same amount of milliequivalents of oxalic acid. Also, remember that the n-factor of KMnO4 varies in acidic and basic medium.
Step-by-Step Solution:
Let us first go through the properties of Potassium Permanganate (KMnO4) as a compound.
Potassium permanganate is an inorganic compound with the chemical formula KMnO4 and composed of K+ and MnO4−. It is a purplish-black crystalline solid that dissolves in water to give intensely pink or purple solutions.
Potassium permanganate is widely used in the chemical industry and laboratories as a strong oxidizing agent, and also as a medication for dermatitis, for cleaning wounds, and general disinfection.
Having established the properties and usage of KMnO4, let us now move on to the particulars of this question.
Now, we know that Oxalic Acid’s chemical formula is COOH−COOH and due to its presence in the initial titration, the medium would thus be acidic.
However, the later titration is done against alkaline H2O2 where the medium would be alkaline in nature.
With all this information now at our disposal along with the hint, let us now proceed to the step-by-step solution: