Question

$100\, mL$ of $0.1 \,M \,H_2SO_4$ is mixed with $100 \,mL$ of $0.1 \,NaOH$ . The normality of the solution obtained is

• A. $0.4\,N$
• B. $0.05\,N$
• C. $0.04\,N$
• D. $0.2\,N$

Answer 1

Answer: (B)

$0.05\,N$

Answer 2

$N_1V_1 = 0.2 \times 100 = 20$
$(0.1\,MH_2SO_4 = 0.2 \,NH_2 SO_4)$ acid
$N_2V_2 = 0.1 \times 100 = 10$ (base)
$N_1V_1$ acid $> N_2V_2$ base hence, resultant mixture is acidic.
Resultant normality
$= \frac{N_1V_1 - N_2V_2}{V_1 + V_2} = \frac{20-10}{200}$
$= \frac{10}{200} = 0.05 \,N$