Question

100 mA current gives a full scale deflection in a galvanometer of resistance 2Ω. The resistance connected with the galvanometer to convert it into a voltmeter of 5 V range is

• A. 98 Ω
• B. 52 Ω
• C. 80 Ω
• D. 48 Ω

Answer 1

Answer: (D)

48 Ω

Answer 2

$R = \frac { V } { I _ { g } } - G = \frac { 5 } { 100 \times 10 ^ { - 3 } } - 2 = 50 - 2 = 48 \Omega$.