Question

$100\,g$ of ice is mixed with $100\,g$ of water at $100^\circ\,C$. What will be the final temperature of the mixture

• A. 10$^\circ$C
• B. 20$^\circ$C
• C. 30$^\circ$C
• D. 40$^\circ$C

Answer 1

Answer: (A)

10$^\circ$C

Answer 2

Let the final temperature be t. Then $100 x 80 + 100 (t- 0) = 100 (100 -t)$ This gives $200 t - 2000$ and $t \,=\, 10^\circ$ C.