Question

10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is:

• A. 100
• B. 1
• C. 1000
• D. 10

Answer 1

Answer: (A)

100

Answer 2

$I_s=\frac{E}{10R}$ ……….(1)

$I_p=\frac{E}{\frac{R}{10}}=\frac{10E}{R}$ ……..(2)

According to eq. (1) and (2)

$n=\frac{I_p}{I_s}=100$

$\Rightarrow n=100$

So, the correct answer is option (A): 100