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Question: 10% of solution of urea is isotonic with 6% solution of a non volatile solute X. what is the molecul...

10% of solution of urea is isotonic with 6% solution of a non volatile solute X. what is the molecular mass of solute X?

A

6gmol16gmol^{- 1}

B

60gmol160gmol^{- 1}

C

36gmol136gmol^{- 1}

D

32gmol132gmol^{- 1}

Answer

36gmol136gmol^{- 1}

Explanation

Solution

No. of mole of urea =1060=16= \frac{10}{60} = \frac{1}{6}

Weight of solute, X=6gX = 6g

No. of moles of X=6MX = \frac{6}{M}

For isotonic solution n1=n2n_{1} = n_{2}

Or 16=6M\frac{1}{6} = \frac{6}{M} or M=36gmol1M = 36gmol^{- 1}