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Question: If A = {2, 4, 6}, then domain of the relation R = {(a, b): a, b ∈ A, |a| - |b| is even number} defin...

If A = {2, 4, 6}, then domain of the relation R = {(a, b): a, b ∈ A, |a| - |b| is even number} defined on A is

A

{2,4}

B

{4,6}

C

{2,6}

D

{2,4,6}

Answer

{2,4,6}

Explanation

Solution

The relation is defined as R={(a,b):a,bA,ab is an even number}R = \{(a, b): a, b \in A, |a| - |b| \text{ is an even number}\}. The set is A={2,4,6}A = \{2, 4, 6\}.

The condition for an ordered pair (a,b)(a, b) to be in RR is that ab|a| - |b| must be an even number. This implies that a|a| and b|b| must have the same parity (both even or both odd).

For any integer xx, x|x| has the same parity as xx. Therefore, the condition "ab|a| - |b| is even" is equivalent to "aa and bb have the same parity".

Let's examine the elements of set A={2,4,6}A = \{2, 4, 6\}:

  • 2 is an even number.
  • 4 is an even number.
  • 6 is an even number.

All elements in set AA are even. So, for any aAa \in A and any bAb \in A, both aa and bb are even. This means they always have the same parity. Consequently, the condition "aa and bb have the same parity" is always satisfied for any a,bAa, b \in A.

This means that every possible ordered pair (a,b)(a, b) where aAa \in A and bAb \in A will satisfy the condition and belong to the relation RR. Thus, the relation RR is the Cartesian product of AA with itself, i.e., R=A×AR = A \times A. R={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)}R = \{(2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6)\}.

The domain of a relation is the set of all first elements of the ordered pairs in the relation. For R=A×AR = A \times A, the first element aa can be any element from set AA. Therefore, the domain of RR is AA.

Domain(R)={2,4,6}(R) = \{2, 4, 6\}.