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Question: 10 gm of ice at 0<sup>0</sup>C is mixed with 10 gm steam at 100<sup>0</sup>C in a container of negli...

10 gm of ice at 00C is mixed with 10 gm steam at 1000C in a container of negligible heat capacity. Amount of steam in the mixture after some time will be (Sw = 1 cal/gm0C, Lv = 540 cal/gm, Lf = 80 cal/gm) –

A

0 gm

B

203\frac{20}{3}gm

C

103\frac{10}{3}gm

D

None of thes

Answer

103\frac{10}{3}gm

Explanation

Solution

Amount of steam required to convert all the ice in water at 1000C is 103\frac{10}{3}gm.