Question

10 gm of ice at 0°C is mixed with 100 gm of water at 50°C. What is the resultant temperature of mixture

• A. 31.2°C
• B. 32.8°C
• C. 36.7°C
• D. 38.2°C

Answer 1

Answer: (D)

38.2°C

Answer 2

$\theta_{\text{mix}} = \frac{m_{W}\theta_{W} - \frac{m_{i}L_{i}}{c_{W}}}{m_{i} + m_{W}}$ $= \frac{100 \times 50 - 10 \times \frac{80}{1}}{10 + 100} \approx 38.2{^\circ}C$