Question

10 g of a gas at NTP occupies 5 litres. The temperature at which the volume becomes double for the same mass of gas at the same pressure is

• A. 273 K
• B. -273$^\circ$C
• C. 273$^\circ$C
• D. 546$^\circ$C

Answer 1

Answer: (C)

273$^\circ$C

Answer 2

According to Charle's law, $\frac{V_1}{T_1} = \frac{V_2}{T_2}$ or $\frac{5}{273} = \frac{10}{T_2}$ $\therefore$ $T_2 = \frac{10}{5} \times$ 273 $= 546 \,K$ or $273^{\circ}$C