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Chemistry Question on Solutions

10.6 g of a substance of a molecular weight 106 was dissolved in 100 mL of this solution 10 mL of this solution was pipetted out in to a 1000 mLflask and made upto the mark with distilled water.The molarity of the resulting solution is

A

1 0 M

B

10−210^{-2}M

C

10−310^{-3}M

D

10−410^{-4}m

Answer

10−210^{-2}M

Explanation

Solution

Initial molarity- =10.6106×1000V(ml)=\frac{10.6}{106} \times \frac{1000}{ V ( ml )} =10.6106×1000100=1M=\frac{10.6}{106} \times \frac{1000}{100}=1 M Now, M1V1=M2V2M _{1} V _{1}= M _{2} V _{2} 1×10=M2×10001 \times 10= M _{2} \times 1000 M2=101000M _{2}=\frac{10}{1000} M2=10−2MM _{2}=10^{-2} M