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Question

Chemistry Question on Surface Chemistry

10410^{-4} g of gelatin is required to be added to 100cm3 100 cm^3 of a standard gold sol to just prevent its coagulation by the addition of 1cm3of101 cm^3 of 10% NaCl solution to it. Hence, the gold number of gelatin is

A

10

B

1

C

0.1

D

0.01

Answer

0.01

Explanation

Solution

By definition, gold number is the number of milligrams of dry protective colloids required to just prevent the coagulation of 10mL10\,mL of red gold sol when 1mL1 mL (or 1cm3)1 \,cm^{3}) of 10%10\% NaClNaCl solution is added to it Here the amount of gelatin required to protect 10mL10 \,mL (or 10cm3)10\, cm^{3}) of gold sol =104×10100=105g=\frac{10^{-4}\times10}{100}=10^{-5}\,g 105×103mg=102mg10^{-5} \times 10^{3}\, mg = 10^{-2}\, mg =0.01mg= 0.01 \,mg \therefore Gold number =0.01= 0.01