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Question: \(10^{- 3}amp\) is flowing through a resistance of \(1000\Omega\). To measure the correct potential ...

103amp10^{- 3}amp is flowing through a resistance of 1000Ω1000\Omega. To measure the correct potential difference, the voltmeter is to be used of which the resistance should be

A

0Ω0\Omega

B

500Ω500\Omega

C

1000Ω1000\Omega

D

>>1000Ω> > 1000\Omega

Answer

>>1000Ω> > 1000\Omega

Explanation

Solution

Resistance of voltmeter should be greater than the external circuit resistance. An ideal voltmeter has infinite resistance.