Question
Question: The number of points of intersection of curve sinx = cosy and x² + y² = 1, is-...
The number of points of intersection of curve sinx = cosy and x² + y² = 1, is-

3
2
0
infinitely many
0
Solution
We need to solve the system:
sinx=cosyandx2+y2=1.Step 1. Rewrite the trigonometric equation
Using the identity cosy=sin(2π−y), we have:
sinx=sin(2π−y).This implies:
(i)x=2π−y+2πkor(ii)x=π−(2π−y)+2πk,where k∈Z.
Simplify (ii):
x=π−2π+y+2πk=2π+y+2πk.So the two cases are:
Case 1: x=2π−y+2πk,Case 2: x=2π+y+2πk.Step 2. Substitute in the circle equation
Since the circle x2+y2=1 restricts x and y to the interval [−1,1], the shifts 2πk (for any k=0) would lead to values far outside this range. Hence, we consider k=0 only.
- For Case 1:
Substitute into the circle:
(2π−y)2+y2=1⟹4π2−πy+2y2=1.This is a quadratic in y:
2y2−πy+(4π2−1)=0.The discriminant D is:
D=π2−4⋅2(4π2−1)=π2−8(4π2−1)=π2−2π2+8=8−π2.Since π2≈9.87, we have D<0. No real solutions exist.
- For Case 2:
Substitute into the circle:
(2π+y)2+y2=1⟹4π2+πy+2y2=1.The quadratic in y is:
2y2+πy+(4π2−1)=0.Its discriminant is:
D=π2−4⋅2(4π2−1)=8−π2,which is also negative.
Thus, in both cases, no real y (and hence no x) satisfy the equations simultaneously.
Step 3. Conclusion
There are no intersection points between the curves.