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Question: The mass of 3.2 x $10^5$ atoms of an element is 8.0 ×$10^{-18}$ g. The atomic mass of the element is...

The mass of 3.2 x 10510^5 atoms of an element is 8.0 ×10−1810^{-18} g. The atomic mass of the element is about (NAN_A = 6 x 102310^{23})

A

2.5 x 10−2210^{-22}

B

15

C

8.0 × 10−1810^{-18}

D

30

Answer

15

Explanation

Solution

  1. Calculate the mass of one atom:
Mass per atom=8.0×10−18 g3.2×105=2.5×10−23 g\text{Mass per atom} = \frac{8.0 \times 10^{-18}\,\text{g}}{3.2 \times 10^5} = 2.5 \times 10^{-23}\,\text{g}
  1. Find the atomic mass by multiplying mass of one atom with Avogadro’s number:
Atomic mass≈2.5×10−23 g×6×1023=15 g/mol\text{Atomic mass} \approx 2.5 \times 10^{-23}\,\text{g} \times 6 \times 10^{23} = 15\,\text{g/mol}