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Question

Chemistry Question on Structure of atom

11 mole of photon, each of frequency 2500s1,2500\,s^{-1}, would have approximately a total energy of :

A

1 erg

B

1 Joule

C

1 eV

D

1 MeV

Answer

1 erg

Explanation

Solution

Frequency of one photon =2500s1=2500\, s ^{-1}
\therefore Frequency of 1 mole of photon
=6.023×1023×2500s1=6.023 \times 10^{23} \times 2500 \,s ^{-1}
Total energy of 11 mole of photon, E=hvE=h v
=6.626×1034Js×6.023×1023×2500s1=6.626 \times 10^{-34} \,Js \times 6.023 \times 10^{23} \times 2500\, s ^{-1}
=9.97×107J10erg=9.97 \times 10^{-7} J \approx 10\, erg
In option (a) there should be 1010 erg instead of 11 erg.