Question

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of $27^{\circ} C$ The work done is $3\, kJ \,mol ^{-1}$ The final temperature of the gas is _______ $K$ (Nearest integer).
Given $C_{ V }=20 \,J\, mol ^{-1} K ^{-1}$

Answer 1

The correct answer is 150.
q=0
ΔU=w
1×20×[T2​−300]=−3000
T2​−300=−150
T2​=150K