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Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant

1 mole of HI is heated in a closed container of capacity of 2 L. At equilibrium half a mole of HI is dissociated. The equilibrium constant of the reaction is

A

0.25

B

1

C

0.35

D

0.5

Answer

0.25

Explanation

Solution

To determine the equilibrium constant of the reaction, we need to know the balanced equation for the dissociation of HI. The balanced equation is: 2HI ⇌ H2 + I2 The expression for the equilibrium constant (Kc) is given by the equation: Kc = [H2] * [I2] / [HI]2 Given that at equilibrium half a mole of HI is dissociated, we can calculate the equilibrium concentrations: [HI] = 0.5 mole / 2 L = 0.25 M [H2] = 0.5 * 0.25 M = 0.125 M [I2] = 0.5 * 0.25 M = 0.125 M Substituting these values into the equilibrium constant expression, we have: Kc = (0.125 M) * (0.125 M) / (0.25 M)2 Kc = 0.015625 / 0.0625 Kc = 0.25 Therefore, the equilibrium constant of the reaction is (A) 0.25.