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Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant

1 mole of H2H_{2} and 2 moles of I2I_{2} are taken initially in a 2 litre vessel. The number of moles of H2H_{2} at equilibrium is 0.2. Then the number of moles of I2I_{2} and HIHI at equilibrium are

A

1.2,1.61.2, 1.6

B

1.8,1.01.8, 1.0

C

0.4,2.40.4, 2.4

D

0.8,2.00.8, 2.0

Answer

1.2,1.61.2, 1.6

Explanation

Solution

At equilibrium number of moles of H2=0.2H_{2} = 0.2 means 0.80.8 moles of H2H_{2 } reacts with (2−0−8)(2 - 0-8) moles of I2I_{2} to form (2×0.8)(2\times 0.8) moles of HIHI H2+I2<=>2HI Initial no. of moles120 No. of moles at equilibrium 0.2(2−0.8)=1.22×0.8=1.6\begin{matrix}&H_{2}&+&I_{2}& {<=>}&2HI&&\\\ \text{Initial no. of moles}&1&&2&&0\\\ \text{No. of moles at equilibrium }&0.2&&(2-0.8)=1.2&&2\times 0.8=1.6\end{matrix}