Question

$1$ mole of gas occupies a volume of $200 \,mL$ at $100 \,mm$ pressure. What is the volume occupied by two moles of gas at $400 \,mm$ pressure and at same temperature?

• A. 50 mL
• B. 100 mL
• C. 200 mL
• D. 400 mL

Answer 1

Answer: (B)

100 mL

Answer 2

Given, $p_{1}=100 \,mm , V_{1}=200 \,mL$ $p_{2}=400\, mm$ From Boyle's law $p_{1} V_{1} =p_{2} V_{2}$ $V_{2} =\frac{P_{1} V_{1}}{P_{2}}$ $=\frac{100 \times 200}{400}$ $V_2 = 50\,mL$ Volume of $2$ mole gas $= 2\times 50$ $= 100\,mL$