Question

1 mole of $FeSO_4$ (atomic weight of Fe is $55.84 \, g \, mol^{-1}$) is oxidized to $Fe_2(SO_4)_3$. Calculate the equivalent weight of ferrous ion

• A. 55.84
• B. 27.92
• C. 18.61
• D. 111.68

Answer 1

Answer: (A)

55.84

Answer 2

Atomic mass of $Fe =55.84$
$\because$ Equivalent mass $=\frac{\text { Atomic mass }}{\text { Change in oxidation state }}$

For the charge, $Fe ^{2+} \longrightarrow Fe ^{3+}$ i.e $(3-2=1)$

the equivalent mass $=\frac{55.84}{1}=55.84$