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Question: 1 mole of an ideal gas A (C v,m = 3R) and 2 mole of an ideal gas B are \(\left( C_{v,m} = \frac{3}{2...

1 mole of an ideal gas A (C v,m = 3R) and 2 mole of an ideal gas B are (Cv,m=32R)\left( C_{v,m} = \frac{3}{2}R \right) taken in a container and expanded reversible and adiabatically from 1 litre to 4 litre starting from initial temperature of 320 K. Δ\DeltaE or Δ\DeltaU for the process is :

A

–240 R

B

–240 R

C

480 R

D

–960 R

Answer

–960 R

Explanation

Solution

Avg. CV, m = n1Cv,m+n2Cv,m2n1+n2\frac{n_{1}C_{v,m} + n_{2}C_{v,m_{2}}}{n_{1} + n_{2}}

= 1×3R+2×32R3\frac{1 \times 3R + 2 \times \frac{3}{2}R}{3} =2R

T1V1g–1 = T2V2g–1 \Rightarrow 320 × 13211^{\frac{3}{2} - 1} = T2 ×(4)3/2–1

\Rightarrow T2 =160 K

Δ\DeltaU = (n1 + n2) CV,avg Δ\DeltaT

= 3 × 2R × (160 – 320) = –960 R