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Question: 1 mole of a monoatomic and 2 mole of diatomic gas are mixed, Now the resulting gas is taken through ...

1 mole of a monoatomic and 2 mole of diatomic gas are mixed, Now the resulting gas is taken through a process in which molar heat capacity was found 3R. Polytropic constant in the process is –

A

15- \frac{1}{5}

B

15\frac{1}{5}

C

25\frac{2}{5}

D

None of these

Answer

15- \frac{1}{5}

Explanation

Solution

C = Cvmix + R1n\frac{R}{1 - n}; Cvmix = n1Cv1+n2Cv2n1+n2\frac{n_{1}Cv_{1} + n_{2}Cv_{2}}{n_{1} + n_{2}}