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Question

Physics Question on kinetic theory

11 mole of a gas with γ=75\gamma = \frac{7}{5} is mixed with 11 mole of gas with γ=53\gamma = \frac{5}{3}, the value of γ\gamma of the resulting mixture of

A

75 \frac{7}{5}

B

25 \frac{2}{5}

C

32 \frac{3}{2}

D

127 \frac{12}{7}

Answer

32 \frac{3}{2}

Explanation

Solution

Cvmixture=52R+32R2C_{v \, mixture} = \frac{\frac{5}{2} R + \frac{3}{2} R}{2} = 2R Cpmixture=C_{p \, mixture} = 2R + R = 2R γmixture=CpmixtureCvmixture=32\gamma_{mixture} = \frac{C_p \, mixture}{C_v \, mixture} = \frac{3}{2}