Question

1 mol ${O_2}$ will be equal to:
A. 4g equivalent oxygen
B. 2g equivalent oxygen
C. 32g equivalent oxygen
D. 8g equivalent oxygen

Answer 1

Hint: - For solving this type of question we must know the definition of the mole and the property of elements that is given in the question.

Complete answer:
Mole of a substance or a particle is defined as exactly $6.02214076 \times {10^{23}}$ particles. Here particles may be atoms, molecules, ions, or electrons. It can also be said that 1 mol particle =$6.02214076 \times {10^{23}}$. Mole is the unit of measurement for the amount of substance in the International System of Units or SI unit.
The number $6.02214076 \times {10^{23}}$ is the Avogadro number and it was chosen so that the mass of one mole of a chemical compound, in grams, is numerically equal to the average mass of one molecule of the compound in Daltons. For example, one mole of water contains $6.02214076 \times {10^{23}}$ molecules, whose total mass is about 18.015 grams and the mean mass of one molecule of water is about 18.015 Daltons.

Normality is defined as the number of grams equivalents present per litre of the solution.
Normality= Molality $\times$n
n= valency = 4 for ${O_2}$
n=2 as oxygen can accept two electrons to complete its octet.
Therefore Normality =1$\times$n
Thus 1 mol of ${O_2}$ will have a 4-gram equivalent.
This is because in an electrode reaction 4 moles of electrons deposit on one mole of ${O_2}$​.
Thus, correct answer is A, which states that 1 mol ${O_2}$will be equal to 4g equivalent oxygen

Note: - In these types of questions we can see the importance of number electrons present in the valence shell of an element and importance of normality, mole etc. Also, we must keep in our mind the Importance of periodic table and the arrangement of elements on it.