Solveeit Logo

Question

Question: 1 M benzoic acid (pKa = 4.20) and 1M C6H5COONa solutions are given separately. What is the volume of...

1 M benzoic acid (pKa = 4.20) and 1M C6H5COONa solutions are given separately. What is the volume of benzoic acid required to prepare a 300 ml buffer solution of pH = 4.5 ? [log 2 = 0.3]

A

200 ml

B

150 ml

C

100 ml

D

50 ml

Answer

100 ml

Explanation

Solution

pH = pKa + log [C6H5COO][C6H5COOH]\frac { \left[ \mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { COO } ^ { - } \right] } { \left[ \mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { COOH } \right] } \Rightarrow 4.5 = 4.2 + log \Rightarrow = 2

\therefore volume of C6H5COONa required = V2 = 200 ml

volume of C6H5COOH required = V1 = 100 ml.