Question

1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution

• A. 0.80 M
• B. 1.0 M
• C. 0.73 M
• D. 0.50 M

Answer 1

Answer: (C)

0.73 M

Answer 2

The correct option is (C) : 0.73 M

Mole of 2.5 L of 1M NaOH =2.5×1=2.5

Mole of 3.0 L of 0.5 M NaOH =3.0×0.5=1.5

Total moles of NaOH in solution =2.5+1.5=4.0 (Total volume of solution =2.5+3.0=5.5L)

Thus, M1 ×V1=M2 ×V2 ​ 4.0=M2 ×5.5 Molarity of resultant solution = M2 = $\frac{4.0}{5.5}$ ​ =0.73M