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Question: Let speed of sound waves in hydrogen gas at room temperature is $v_0$. What will be the speed of sou...

Let speed of sound waves in hydrogen gas at room temperature is v0v_0. What will be the speed of sound waves in a room which contains an equimolar mixture of hydrogen and 'He' at same temperature :-

A

75v0\sqrt{\frac{7}{5}}v_0

B

57v0\sqrt{\frac{5}{7}}v_0

C

52v0\sqrt{\frac{5}{2}}v_0

D

None

Answer

57v0\sqrt{\frac{5}{7}}v_0

Explanation

Solution

The speed of sound in an ideal gas is given by v=γRTMv = \sqrt{\frac{\gamma RT}{M}}.

For hydrogen (H2H_2), γH2=7/5\gamma_{H_2} = 7/5 and MH22g/molM_{H_2} \approx 2 \, g/mol. v0=(7/5)RT2v_0 = \sqrt{\frac{(7/5) RT}{2}}.

For helium (HeHe), γHe=5/3\gamma_{He} = 5/3 and MHe4g/molM_{He} \approx 4 \, g/mol.

For an equimolar mixture of hydrogen and helium: Effective molar mass Mmix=0.5×MH2+0.5×MHe=0.5×2+0.5×4=1+2=3g/molM_{mix} = 0.5 \times M_{H_2} + 0.5 \times M_{He} = 0.5 \times 2 + 0.5 \times 4 = 1 + 2 = 3 \, g/mol.

The specific heats are Cv,H2=RγH21=R7/51=5R2C_{v, H_2} = \frac{R}{\gamma_{H_2}-1} = \frac{R}{7/5-1} = \frac{5R}{2} and Cv,He=RγHe1=R5/31=3R2C_{v, He} = \frac{R}{\gamma_{He}-1} = \frac{R}{5/3-1} = \frac{3R}{2}. The specific heat at constant volume for the mixture is Cv,mix=0.5×Cv,H2+0.5×Cv,He=0.5×5R2+0.5×3R2=R2(52+32)=R2(4)=2RC_{v, mix} = 0.5 \times C_{v, H_2} + 0.5 \times C_{v, He} = 0.5 \times \frac{5R}{2} + 0.5 \times \frac{3R}{2} = \frac{R}{2} (\frac{5}{2} + \frac{3}{2}) = \frac{R}{2} (4) = 2R. The specific heat at constant pressure for the mixture is Cp,mix=Cv,mix+R=2R+R=3RC_{p, mix} = C_{v, mix} + R = 2R + R = 3R. The adiabatic index for the mixture is γmix=Cp,mixCv,mix=3R2R=32\gamma_{mix} = \frac{C_{p, mix}}{C_{v, mix}} = \frac{3R}{2R} = \frac{3}{2}.

The speed of sound in the mixture is vmix=γmixRTMmix=(3/2)RT3v_{mix} = \sqrt{\frac{\gamma_{mix} RT}{M_{mix}}} = \sqrt{\frac{(3/2) RT}{3}}.

The ratio of the speeds is: vmixv0=(3/2)RT3(7/5)RT2=(3/2)/3(7/5)/2=1/27/5=12×57=57\frac{v_{mix}}{v_0} = \frac{\sqrt{\frac{(3/2) RT}{3}}}{\sqrt{\frac{(7/5) RT}{2}}} = \sqrt{\frac{(3/2)/3}{(7/5)/2}} = \sqrt{\frac{1/2}{7/5}} = \sqrt{\frac{1}{2} \times \frac{5}{7}} = \sqrt{\frac{5}{7}}. Therefore, vmix=57v0v_{mix} = \sqrt{\frac{5}{7}} v_0.