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Question

Chemistry Question on Gas laws

1 L1 \,L of a gas is at a pressure of 10−6 mm10^{-6} \, mm of Hg at 25∘C25^{\circ} C. How many molecules are present in the vessel?

A

3.2×1063.2 \times 10^6

B

3.2×10133.2 \times 10^{13}

C

3.2×10103.2 \times 10^{10}

D

3×1043 \times 10^4

Answer

3.2×10133.2 \times 10^{13}

Explanation

Solution

ρ1V1T1=ρ2V2T2\frac{\rho_{1} V _{1}}{ T _{1}}=\frac{\rho_{2} V _{2}}{ T _{2}}
⇒10−6×1000298=760×V2273\Rightarrow \frac{10^{-6} \times 1000}{298}=\frac{760 \times V _{2}}{273}
V2=1.2×10−6cc(V _{2}=1.2 \times 10^{-6} cc ( at STP)\quad STP )
No. of molecules =6.02×102322400×1.2×10−6=\frac{6.02 \times 10^{23}}{22400} \times 1.2 \times 10^{-6}
=3.2×1013=3.2 \times 10^{13}