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Question

Physics Question on work, energy and power

11 kilowatt hour (kWh)(kWh) is equal to

A

2.25×1022 eV2.25 \times 10^{22}\, eV

B

2.25×1023 eV2.25 \times 10^{23}\, eV

C

2.25×1025 eV2.25 \times 10^{25}\, eV

D

2.25×1027 eV2.25 \times 10^{27}\, eV

Answer

2.25×1025 eV2.25 \times 10^{25}\, eV

Explanation

Solution

11 kilowatt hour (kW h)=(103 W)×(3600 s)(kW \,h) = (10^3\, W) \times (3600 \,s) =3.6×106 J=3.6×1061.6×10−19eV(∵1 eV=1.6×10−19 J)= 3.6 \times 10^{6}\,J = \frac{3.6 \times 10^{6}}{1.6 \times10^{-19}} eV \left(\because 1\,eV = 1.6 \times 10^{-19}\,J\right) =2.25×1025 eV= 2.25 \times 10^{25}\,eV